# How to make a quadratic equation solver in python?

In this post I would be writing a guide on how to make a quadratic equation solver where you input a,b and c into the equation:

Plan

• Inputs
• Solve the equation

Maths

First we need to understand how we are going to solve an quadratic equation. I used the quadratic equation. I also made my code print no real solutions when the discriminant is less than 0. The quadratic equation The discriminant.

Inputs

```print('ax^2 + bx + c = 0')
A=int(input('a = '))
B=int(input('b = '))
C=int(input('c = '))
```

print(‘ax^2 + bx + c = 0’)

This is to tell the user what a,b and c represent.

Solve the equation

```Discriminant=math.sqrt((B*B)-(4*A*C))
if Discriminant<(0):
print('No real values')
else:
print('x = '+str( ((0-B)+Discriminant)/(2*A) ))
print('x = '+str( ((0-B)-Discriminant)/(2*A) ))
```

Discriminant=math.sqrt((BB)-(4A*C))

I had to use the math module to do “math.sqrt()”. I did import math at the top of my code.

if Discriminant<(0):
print(‘No real values’)

This checks if the values have a solution

((0-B)+Discriminant)/(2*A)
((0-B)-Discriminant)/(2*A)

This subs the values into the quadratic equation.

The full code

```#imports
import math

#Inputs
print('ax^2 + bx + c = 0')
A=int(input('a = '))
B=int(input('b = '))
C=int(input('c = '))

#Solve the equation
Discriminant=math.sqrt((B*B)-(4*A*C))
if Discriminant<(0):
print('No real values')
else:
print('x = '+str( ((0-B)+Discriminant)/(2*A) ))
print('x = '+str( ((0-B)-Discriminant)/(2*A) ))
``` This is what the program looks like when ran.